博客
关于我
强烈建议你试试无所不能的chatGPT,快点击我
Sorting It All Out(拓扑排序)
阅读量:6902 次
发布时间:2019-06-27

本文共 3011 字,大约阅读时间需要 10 分钟。

题目:

An ascending sorted sequence of distinct values is one in which some form of a less-than operator is used to order the elements from smallest to largest. For example, the sorted sequence A, B, C, D implies that A < B, B < C and C < D. in this problem, we will give you a set of relations of the form A < B and ask you to determine whether a sorted order has been specified or not.

Input

Input consists of multiple problem instances. Each instance starts with a line containing two positive integers n and m. the first value indicated the number of objects to sort, where 2 <= n <= 26. The objects to be sorted will be the first n characters of the uppercase alphabet. The second value m indicates the number of relations of the form A < B which will be given in this problem instance. Next will be m lines, each containing one such relation consisting of three characters: an uppercase letter, the character "<" and a second uppercase letter. No letter will be outside the range of the first n letters of the alphabet. Values of n = m = 0 indicate end of input.

Output

For each problem instance, output consists of one line. This line should be one of the following three: 
Sorted sequence determined after xxx relations: yyy...y. 
Sorted sequence cannot be determined. 
Inconsistency found after xxx relations. 
where xxx is the number of relations processed at the time either a sorted sequence is determined or an inconsistency is found, whichever comes first, and yyy...y is the sorted, ascending sequence. 

Sample Input

4 6A

Sample Output

Sorted sequence determined after 4 relations: ABCD.Inconsistency found after 2 relations.Sorted sequence cannot be determined. 题意:输入n,m,n和m为0的时候输入结束,n代表n个字母,接下来输入m组数据,然后让你根据这m组数据判断是否能将这m个字母排序好,要注意在第i组数据能排序好的时候就输出结果,接下来的数据值输入,不进行判断; 分析:这是我第一次做有于拓扑排序有关的题目,根据题意我们需要分为三步:①判断是否形成循环 ②判断是否有序 ③无法判断(题目输入的数据不足以判断) AC代码:
#include
#include
#include
#include
#include
#include
using namespace std;#define N 30char Map[N][N];int indegree[N],p[N];int c;int toposort(int n){ c=0; int sign=1; int temp[N],m,now; for (int i=1;i<=n;i++) temp[i]=indegree[i]; for (int i=1;i<=n;i++) { m=0; for (int j=1;j<=n;j++) if (temp[j]==0) m++,now=j; if (m==0) return 0; //成环 if (m>1) sign=-1; //无法判断 p[c++]=now; temp[now]=-1; for (int j=1;j<=n;j++) if (Map[now][j]==1) temp[j]--; } return sign; //有序}int main(){ int n,m; char w[5]; int x,y; while (scanf("%d%d",&n,&m)&&(n!=0||m!=0)) { int flag=0; memset(Map,0,sizeof(Map)); memset(indegree,0,sizeof(indegree)); for (int i=1;i<=m;i++) { scanf("%s",w); if (flag) continue; x=w[0]-'A'+1; y=w[2]-'A'+1; Map[x][y]=1; //x->y indegree[y]++; //后者入度+1 int t=toposort(n); if (t==0) printf("Inconsistency found after %d relations.\n",i),flag=1; else if (t==1) { printf("Sorted sequence determined after %d relations: ",i); for(int j=0;j

 

转载于:https://www.cnblogs.com/lisijie/p/7806044.html

你可能感兴趣的文章
我的友情链接
查看>>
UITabelView的分割线处理及介绍
查看>>
Spring整合MyBatis
查看>>
打印机拒绝访问无法连接
查看>>
Linux学习路线图
查看>>
Linux系统下常见性能分析工具的使用
查看>>
事件驱动模型
查看>>
ASP.NET MVC 音乐商店 - 3. 视图与模型
查看>>
mcollective安装文档
查看>>
GRE隧道模式与IPSec传输模式构建×××
查看>>
linux命令6--touch命令
查看>>
我的友情链接
查看>>
且谈布局适配和日志框架
查看>>
在论坛中出现的比较难的sql问题:15(行转列2)
查看>>
springboot中的5种通知小例子
查看>>
mysql数据通过jdbc操作作为Spark数据源案例
查看>>
Sersync实现触发式文件同步
查看>>
shell练习题
查看>>
大型网站压力测试及优化方案
查看>>
云计算的特性有这4点
查看>>